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Home/ Questions/Q 976843
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T03:48:38+00:00 2026-05-16T03:48:38+00:00

String messageFile = … // Assume messageFile SHOULD have the string MESSAGE System.out.println(The messageFile

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String messageFile = ... // Assume messageFile SHOULD have the string "MESSAGE"
System.out.println("The messageFile is: " + messageFile + "!!");

Normally, one would expect the above command to output:

The messageFile is: MESSAGE!!!!

However, I am receiving this instead:

!!e messageFile is: MESSAGE

See how the above statement, the “!!” points seem to wrap around the message. My theory is that the:

String messageFile = ... 

contains more characters than my assumed “MESSAGE”. As a result, it’s wrapping the next input (in this case, the “!!”) to the front of the System.out.println() message.

What character is causing this?

Extra info:

Btw, messageFile is being initialized by passing a command line argument to a java class, myClassA. myClassA’s constructor uses a super() to pass the messageFile parameter to myClassB. myClassB passes messageFile into a function().

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  1. Editorial Team
    Editorial Team
    2026-05-16T03:48:40+00:00Added an answer on May 16, 2026 at 3:48 am

    I would guess you have a stray carriage return (\r) within the messageFile variable that is unaccompanied by a line feed (\n).

    EDIT – this tests as expected:

    class Println {
            public static void main(String[] args) {
                    System.out.println("xxxx this \rTEST");
            }
    }
    

    Output:

    TEST this 
    
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