Question

String s = "128166947252913248";
DecimalFormat df = new DecimalFormat("##########################.########");
Double oldTime1 = new Double(s); 
Double oldTime2 = new Double("128166947252913249"); 
Double oldTime3 = new Double("128166947252913247");
Double newTime = new Double("116444736000000000");
System.out.println(newTime.longValue());
System.out.println(df.format(oldTime1));
System.out.println(oldTime1-newTime);
System.out.println(df.format(oldTime1-newTime));
System.out.println(df.format(oldTime3-newTime));

Output is :

116444736000000000
128166947252913248
1.1722211252913248E16
11722211252913248
11722211252913248

This is the code I am working on. I am unable to stop double variable getting truncated at the last variable. Please help me to get a value without being truncated.

Answer 1

Try Using BigDecimal

String s = "128166947252913248";
DecimalFormat df = new DecimalFormat(
        "##########################.########");
BigDecimal oldTime1 = new BigDecimal(s);
BigDecimal oldTime2 = new BigDecimal("128166947252913249");
BigDecimal oldTime3 = new BigDecimal("128166947252913247");
BigDecimal newTime = new BigDecimal("116444736000000000");
System.out.println(newTime.longValue());
System.out.println(df.format(oldTime1));
System.out.println(oldTime1.subtract(newTime));
System.out.println(df.format(oldTime1.subtract(newTime)));
System.out.println(df.format(oldTime3.subtract(newTime)));