Question

String s = "java";
s.substring(1); // ava

Considering the immutability of strings, compiler doesnot modify 's' but creates a new object or you can say that there is space for 'java' as well as 'ava' in memory..

What happens to this 'ava', as nothing is pointing to it or it’s not being referenced by anything..

One more question… If i would have written String s = new String("java"); // ‘java’ is not in string literal pool….

The ‘ava’ would be in the string literal pool then or not ?

Answer 1

What happens to this ‘ava’, as nothing is pointing to it or it’s not being referenced by anything..

The newly constructed String object immediately becomes eligible for garbage collection.

As to your second question, I don’t think there’s any difference between the following two expressions as far as the string literal pool is concerned:

String s = "java";
String s = new String("java");

In both cases, the literal "java" would be in the pool. (But in the second case, s would not refer to the "java" string that’s in the pool, but to a different String that also has the characters "java".)