Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 658329
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T22:55:17+00:00 2026-05-13T22:55:17+00:00

string str = one three; string::iterator it; string add = two ; Lets say

  • 0
string str = "one three";
string::iterator it;
string add = "two ";

Lets say I want to add: “two ” right after the space in “one”.
the space would be str[3] correct? so: in this case, n = 3;

for (it=str.begin(); it < str.end(); it++,i++) 
{
  if(i == n) 
  {                   
    // insert string add at current position          
    break;
  } // if at correct position
} // for

*it would allow me to access the character at str[3], but I don’t know how I would add in the string from there. Any help is appreciated, thanks. If anything is confusing or unclear please let me know

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T22:55:18+00:00Added an answer on May 13, 2026 at 10:55 pm

    You can make use of the insert method of the string class.

    string str = "one three";
    string add = "two ";
    str.insert(4,add); // str is now "one two three"
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 505k
  • Answers 505k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer to give it a name you use this syntax register_sidebar(array(… May 16, 2026 at 3:24 pm
  • Editorial Team
    Editorial Team added an answer I believe what you want to do can be achieved… May 16, 2026 at 3:24 pm
  • Editorial Team
    Editorial Team added an answer Your best bet is probably to sample both your offscreen… May 16, 2026 at 3:24 pm

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Related Questions

Given the following string: var str = one,two,three; If I split the string on
I have one string var str = ''; str += 'category='+jv('category')+'&'; str += 'refresh_rate='+jv('refreshRate')+'&';
I'm using Reportlab to create PDFs. I'm creating two PDFs which I want to
I have this method declaration in Util.h file 30:string to_string(const bit_vector& v); Util.cc file
The STL commonly defines an output iterator like so: template<class Cont> class insert_iterator :
I am querying the registry on Windows CE. I want to pull back the
In my test.php I would like to provide a link back to the production
Note: Edited based on responses to receive more appropriate answers. I have a collection
What could cause this? Here's the stack trace: #0 0x0645c0f5 in std::_Rb_tree_increment (__x=0x83ee5b0) at
Is there any reason that the ctype facet functions ( is , scan_is ,

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.