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Home/ Questions/Q 7992809
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T13:40:35+00:00 2026-06-04T13:40:35+00:00

String url = mysite.com/index.php?name=john&id=432 How can I extract the id parameter (432)? it can

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String url = "mysite.com/index.php?name=john&id=432"

How can I extract the id parameter (432)?

it can be in any position in the url and the length of the id varies too

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  1. Editorial Team
    Editorial Team
    2026-06-04T13:40:36+00:00Added an answer on June 4, 2026 at 1:40 pm

    You can use Apache URLEncodedUtils from HttpClient package:

    import org.apache.http.NameValuePair;
    import org.apache.http.client.utils.URLEncodedUtils;
    import java.nio.charset.Charset;
    import java.util.List;
    
    public class UrlParsing {
        public static void main(String[] a){
            String url="http://mysite.com/index.php?name=john&id=42";
            List<NameValuePair> args= URLEncodedUtils.parse(url, Charset.defaultCharset());
            for (NameValuePair arg:args)
                if (arg.getName().equals("id"))
                    System.out.println(arg.getValue());
        }
    }
    

    This print 42 to the console.

    If you have the url stored in a URI object, you may find useful an overload of URLEncodedUtils.parse
    that accept directly an URI instance. If you use this overloaded version, you have to give the charset as a string:

    URI uri = URI.create("http://mysite.com/index.php?name=john&id=42");
    List<NameValuePair> args= URLEncodedUtils.parse(uri, "UTF-8");
    
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