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Home/ Questions/Q 7402607
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T04:47:03+00:00 2026-05-29T04:47:03+00:00

struct A { template <class U> void f(U) { } }; template <class T>

  • 0
struct A
{
    template <class U> 
    void f(U)
    {

    }
};

template <class T>
void f(T t) 
{
    A a;
    a.template f<int>(t);
    a.template f<>(t);
    a.f<int>(t);
    a.f<>(t);
    a.f(t);
}

At least under MSVC2010 the above code compile fine.

Among all the manners to call A.f is there any preferentials way to do this?

Is there any differences ?

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  1. Editorial Team
    Editorial Team
    2026-05-29T04:47:05+00:00Added an answer on May 29, 2026 at 4:47 am

    Well, a has type A, which is not a dependent type in this context. So the template keyword is not needed and only serves to obfuscate the code — don’t use it.

    The version that invokes a template without supplying any arguments, again does nothing to change behavior and only makes the code less readable — don’t use it either.

    Between the two remaining candidates, a.f(t) and a.f<int>(t), use the first in most cases, and the second if the compiler fails to deduce the type.

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