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Home/ Questions/Q 4618650
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T02:17:50+00:00 2026-05-22T02:17:50+00:00

struct A {}; typedef A B; struct C { friend struct B; }; GCC

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struct A {};
typedef A B;

struct C { friend struct B; };

GCC 4.7.0 20110427 tells me error: using typedef-name 'B' after 'struct'.

So far, this seems pretty self-explanatory; after all, my example code is trying to declare-and-friend a struct called B, which is in fact not a struct-key.

However, I have to write friend struct A; if A is in fact a complex, long-winded mess of template metahackery, this is not desirable.

Am I missing something, or can we in fact not friend types through type aliases? If not, is there any particular reason or is it just a quirk of the language?


This question brought up the issue before, but is dated and makes assertions on the matter regarding C++0x that don’t appear to be true. This question instead regards the C++0x FDIS.

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  1. Editorial Team
    Editorial Team
    2026-05-22T02:17:50+00:00Added an answer on May 22, 2026 at 2:17 am

    You can befriend arbitrary types (for non-class types, the friend declaration will be ignored), but then you shall omit struct:

    struct A {};
    typedef A B;
    
    struct C { 
      friend B; // equivalent: friend struct A;
                // equivalent: friend A;
    
      friend int; // ignored
    };
    
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