Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8514419
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 11, 20262026-06-11T04:51:49+00:00 2026-06-11T04:51:49+00:00

struct ifreq { char ifr_name[IFNAMSIZ]; union { caddr_t ifr_d; } ifr; }; Here they

  • 0
struct  ifreq {
    char    ifr_name[IFNAMSIZ];             
    union {
            caddr_t ifr_d;
    } ifr;
};

Here they have used union, I didn’t get the point why have they used when there is only one element used there?
I have a idea of using union only if there are 2-3 elements that need to be used.

Thanks

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-11T04:51:51+00:00Added an answer on June 11, 2026 at 4:51 am

    Loads of possibilities. But, in this case, it looks like it’s because the definition was cut out of the corresponding Linux header, and they just took the parts they needed. struct ifreq looks like this, normally:

    struct ifreq {
        char ifr_name[IFNAMSIZ]; /* Interface name */
        union {
            ...
        };
    };
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have got MAC address as under. struct ifreq ifr; struct ifreq *IFR; struct
I have a struct struct request { int code; char *message; }; that I'd
struct myType { vector<char*> ls; }; Here ls is holding pointers to char .
I am working with the following code: struct sockaddr_in6 *sin; struct ifreq ifr; sin
struct { char a; int b; } x; Why would one define a struct
struct Drink { public string Name { get; private set; } public int Popularity
struct match { char men[64]; char women[64]; char menNum[1000]; char woNum[1000]; }; void printOut();
struct SomeStruct { public int Num { get; set; } } class Program {
int ScanDirectories(const char *dirname, struct images *imagesHeadPtr, struct filesToParse *filesHeadPtr) { // scan the
I am using ioctl(s, SIOCSIFMTU, (caddr_t)&ifr) to change the MTU for an interface. code

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.