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Asked: 2026-05-27T15:59:32+00:00

struct node { double a : 23; int b; }s; int main() { printf(%d\n,sizeof(s));

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struct node
{
    double a : 23;
    int b;
}s;
int main()
{    
    printf("%d\n",sizeof(s));
}

Why do this produce a compile error? I want to know why we cannot do bit-fields with double datatype.

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1 Answer

  1. Editorial Team

    Quoted from Wiki :

    C also provides a special type of structure member known as a bit field, which is an integer with an explicitly specified number of bits. A bit field is declared as a structure member of type int, signed int, unsigned int, or _Bool, following the member name by a colon (:) and the number of bits it should occupy. The total number of bits in a single bit field must not exceed the total number of bits in its declared type.

    in the statement double a : 23; you are using bit field for double which is an error.You should use int instead.

    Edit:
    The Behavior is implementation dependent use anything other than these.Char may work on your system but it may fail on other platform as it’s not part of standard.

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