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Editorial Team
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Asked: 2026-06-08T18:33:44+00:00

Struggling to get this query working: $query_search = SELECT questionnaires_index.id, questionnaires_index.ea_num, questionnaires_index.address, questionnaires_index.status, questionnaires_index.json_stored

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Struggling to get this query working:

$query_search = "SELECT questionnaires_index.id, questionnaires_index.ea_num, questionnaires_index.address, questionnaires_index.status, questionnaires_index.json_stored users.username FROM questionnaires_index INNER JOIN users ON questionnaires_index.interviewer_id = users.id WHERE questionnaires_index.interviewer_id IN (SELECT GROUP_CONCAT(id) FROM users WHERE supervisor = (SELECT id FROM users WHERE username = '".$username."'))";

Getting this error:

Error in query: . You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near ‘.username FROM questionnaires_index INNER JOIN
users ON users.id = questionnaire’ at line 1

The query was working until I added the users.username to the result set with the JOIN statement. Any help please.

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1 Answer

  1. Editorial Team

    You have missed a comma

    $query_search = “SELECT questionnaires_index.id, questionnaires_index.ea_num, questionnaires_index.address, questionnaires_index.status, questionnaires_index.json_stored, users.username FROM questionnaires_index INNER JOIN users ON questionnaires_index.interviewer_id = users.id WHERE questionnaires_index.interviewer_id IN (SELECT GROUP_CONCAT(id) FROM users WHERE supervisor = (SELECT id FROM users WHERE username = ‘”.$username.”‘))”;

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