(sub {
print 1;
})();
sub {
print 1;
}();
I tried various ways, all are wrong…
(sub { print 1; })(); sub { print 1; }(); I tried various ways,
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(sub { ... })will give you the pointer to the function so you must call by reference.(sub { print "Hello world\n" })->();The other easy method, as pointed out by Blagovest Buyukliev would be to dereference the function pointer and call that using the
{ }operators&{ sub { print "Hello World" }}();