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Home/ Questions/Q 6981035
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Editorial Team
  • 0
Editorial Team
Asked: May 27, 20262026-05-27T18:06:16+00:00 2026-05-27T18:06:16+00:00

<subjectOf typeCode=SUBJ> <annotation classCode=ACT moodCode=EVN> <realmCode code=QD /> <code code=SPECIALNOTE></code> <text><![CDATA[<strong>** New York State

  • 0
<subjectOf typeCode="SUBJ">
    <annotation classCode="ACT" moodCode="EVN">
        <realmCode code="QD" />
        <code code="SPECIALNOTE"></code>
        <text><![CDATA[<strong>** New York State approval pending. This test is not available for New York State patient testing **</br> ]]></text>
    </annotation>
</subjectOf>
<subjectOf typeCode="SUBJ">
    <annotation classCode="ACT" moodCode="EVN">
        <realmCode code="QD" />
        <code code="PREFERREDSPECIMEN"></code>
        <text><![CDATA[2 mL Second void urine <strong>or </strong>2-hour urine <strong>or </strong>&nbsp;2 mL Urine with no preservative]]></text>
    </annotation>
</subjectOf>

In DOM parsing, how can I traverse through the above XML and get the <text> tag value depending upon a <code> tag attribute having a given value. For example, I want to get the following text:

<strong>** New York State approval pending. This test is not available
for New York State patient testing **</br>

…based on the <code> tag with a code attribute where value="SPECIALNOTE".

public static void main(String[] args) throws ParserConfigurationException, SAXException, IOException, XPathExpressionException {      
    DocumentBuilderFactory domFactory =  DocumentBuilderFactory.newInstance();          
    domFactory.setNamespaceAware(true);      
    DocumentBuilder builder = domFactory.newDocumentBuilder();     
    Document doc = builder.parse("xml.xml");     
    XPath xpath = XPathFactory.newInstance().newXPath();        // XPath Query for showing all nodes value     

    XPathExpression expr = xpath.compile("/testCodeIdentifier/subjectOf/subjectOf/annotation/code[@code='SPECIALNOTE']");      
    Object result = expr.evaluate(doc, XPathConstants.NODESET);     
    NodeList nodes = (NodeList) result;     
    for (int i = 0; i < nodes.getLength(); i++) {      
        System.out.println("........"+nodes.item(i).getNodeValue()+"........");      
        }   
    } 
}

Appreciate the help in advance…

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T18:06:17+00:00Added an answer on May 27, 2026 at 6:06 pm

    Finally i have got the answer for my question by myself…. Below code is being working for my XML to be parsed…

      XPath xpath = XPathFactory.newInstance().newXPath();
       // XPath Query for showing all nodes value
      XPathExpression expr = xpath.compile("//testCodeIdentifier/subjectOf/order/subjectOf/annotation/code[@code='SPECIALNOTE']/following-sibling::text/text()");
    
      Object result = expr.evaluate(doc, XPathConstants.NODESET);
      NodeList nodes = (NodeList) result;
      for (int i = 0; i < nodes.getLength(); i++) {
    
          System.out.println(nodes.item(i).getNodeValue()); 
    
      }
    

    Thank you people who have ansewered in this post but this is a possible solution for it. Have a mark on it.

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