Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 5941873
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 22, 20262026-05-22T16:10:18+00:00 2026-05-22T16:10:18+00:00

$(#submit).click(function(){ $.ajax({ type: POST, url: session.php, data: name=John123&location=Boston, success: function(a, msg2){ $(‘#feedback’).removeClass().addClass(‘success’).text(a +’ ‘+msg2).fadeIn(‘slow’);

  • 0
 $("#submit").click(function(){
    $.ajax({
       type: "POST",
       url: "session.php",
       data: "name=John123&location=Boston",
       success: function(a, msg2){
          $('#feedback').removeClass().addClass('success').text(a +' '+msg2).fadeIn('slow');

       },

         error: function(a, b, c){
              $('#feedback').removeClass().addClass('error').text('This is' +b).fadeIn('slow');
           },

I’m trying to invoke error function using the following code in PHP:

if ($_POST['name'] != "John") {
        $message['error'] = true;
        $message['message'] = "Hmm, please enter a subject in the subject field.";

        echo json_encode($message);
}
else
{
    echo $_POST['name'];
}

But I’m always getting success function invoked. Is there any way i can get error function invoked.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-22T16:10:19+00:00Added an answer on May 22, 2026 at 4:10 pm

    Why won’t you do something like this:

    $("#submit").click(function(){
        $.ajax({
            type: "POST",
            url: "session.php",
            data: "name=John&location=Boston",
            success: function(a, msg2){
                if(a.error) {
                    $('#feedback').removeClass().addClass('error').text('This is' +a.message).fadeIn('slow');
                }
                else {
                    $('#feedback').removeClass().addClass('success').text(a.name +' '+msg2).fadeIn('slow');
                }
            }
        });
    });
    

    And:

    if ($_POST['name'] != "John") {
        $message['error'] = true;
        $message['message'] = "Hmm, please enter a subject in the subject field.";
    }
    else
    {
        $message['error'] = false;
        $message['name'] = $_POST['name'];
    }
    echo json_encode($message);
    

    The error function is invoked only when the ajax fails, so instead you can check if the ajax returned that the error exists or not.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

<script type=text/javascript> var dataString2 = 'run=captchagood&comment=' + comment; $.ajax({ type: POST, url: process.php, data:
ajaxSubmit.js: $(document).ready(function(){ $('#submit').click(function() { $('#waiting').show(500); $('#reg').hide(0); $('#message').hide(0); $.ajax({ type : 'POST', url : 'post.php',
Here is my jQuery code: <script type=text/javascript> //<!-- $(document).ready(function() { $('input[type=submit]').click(function() { $.ajax({ type:
Hey What am I doing wrong here? Extremely new to ajax. $(document).ready(function(){ $('#submit').click(function() {
I have the following JS $('#Submit').click(function () { var name = $('#Name').val(); var age
I'm trying to submit a form with AJAX through jQuery: $('.submit input').click(function() {return false;});
Here is what I have going on in my AJAX: $('#submit-button').click(function(){ var twit =
The following code does not submit the input values: $('.button').live('click', function() { var date
$(#submit-button).click(function() { if($.trim($(#email).val()) === ) { $(.error-message-email).show(); } if($.trim($(#password).val()) === ){ $(.error-message-password).show(); } return
$(#submit).click(function () { var boolError = false; CheckForm(#email); CheckPhone(#phone); if (boolError == true) {

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.