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Editorial Team
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Asked: 2026-06-08T03:11:17+00:00

$(#submitbutton).button().click(function() { $.ajax({ type: ‘POST’, url: ‘tst/mmm.php’, data: { abc: abcdefghijklmnopqrstuvwxyz }, success: function(msg){

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$("#submitbutton").button().click(function() {
    $.ajax({
        type: 'POST',
        url: 'tst/mmm.php',
        data: { abc: "abcdefghijklmnopqrstuvwxyz" },
        success: function(msg){
            alert(msg);
        }
    });
});

# cat tst/mmm.php
<?php echo json_encode(array("first"=>"YyXy","last"=>"yyyyXXX")); ?>

Why cant i see an alert that tells me first=YyXy&last=yyyyXXX . if it means anything, there is access to mmm.php from remote. They are both on apache. Where should i look for the response of this post? Sorry for the lame questions in the subject,i’m new to it. Thanx!!

EDIT 1: html code:

 <body>
            <div id=container>
            <div id="first">
                    <form id='form1'>
                            <button id="submitbutton" type="submit">Submit</button></br></br>
                    </form>
            </div>

EDIT 2 :
Do I need special user:group permissions for the html to post to php?
Should I use some special settings to allow access to mmm.php in apache configuration (httpd.conf) ?

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1 Answer

  1. Editorial Team

    Well, In the docs they state the following:

    Deprecation Notice: The jqXHR.success(), jqXHR.error(), and
    jqXHR.complete() callbacks
    will be deprecated in jQuery 1.8. To prepare your code for their eventual removal, use
    jqXHR.done(), jqXHR.fail(), and jqXHR.always() instead.

    so i used their example and now it looks like that(and works) :

    $("#submitbutton").button().click(function() {
    $.ajax({
        type: 'POST',
        url: 'mmm.php',
        data: { abc: "abcdefghijklmnopqrstuvwxyz" } })
        .done(function() { alert("success"); })
        .fail(function() { alert("error"); })
        .always(function() { alert("complete"); });
   });
});

    thank you guys!!

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