Question

Suppose:

  6   char arr[] = "ABC";
  7 
  8   char *ptr   = &arr;
  9   char *ptr2  = &ptr;

Using ptr2, how can i access elements of c?

I would have thought the following would work, but … it does not.

**ptr2[1]

Answer 1

You currently don’t have a pointer-to-a-pointer.

Your code should be:

char c[] = "ABC";

char  *ptr  = c;     // Note no &
char **ptr2 = &ptr;  // Note **, not *.  This is now a pointer-to-pointer

Then to access, you want this:

(*ptr2)[1]