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Home/ Questions/Q 7028707
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T00:26:38+00:00 2026-05-28T00:26:38+00:00

Suppose a Ruby project with the following structure… project/ |– data | `– data.yaml

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Suppose a Ruby project with the following structure…

project/
|-- data
|   `-- data.yaml
|-- lib
|   |-- project
|   |   `-- myclass.rb
|   `-- project.rb

Within lib/project/myclass.rb, I load data/data.yaml as shown in the example below…

def MyClass
  data = YAML::load(File.open('../../data/data.yaml'))
  # Other stuff..
end

Within lib/project.rb, I include project/myclass.rb

If project.rb is run, the following error will be thrown…

Errno::ENOENT: No such file or directory - ../../data/data.yaml

In order to get around this, I have to update the file path used in myclass.rb so that it is relative to the root or the lib directory…

../data/data.yaml

Is there a better way to handle this?

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  1. Editorial Team
    Editorial Team
    2026-05-28T00:26:38+00:00Added an answer on May 28, 2026 at 12:26 am

    You can load the data like this:

    filename = File.join File.dirname(__FILE__), '..', '..', 'data', 'data.yaml'
    data = YAML::load File.open filename
    

    The way you are currently doing it is kind of bad because it imposes requirements on the user’s current directory when he runs your code.

    Alternatively, you can embed the YAML data at the end of your ruby file using the __END__ keyword.

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