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Asked: 2026-06-12T16:11:02+00:00

suppose an object can have multiple tids now suppose I do this query: SELECT

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suppose an object can have multiple tids

now suppose I do this query: 

SELECT n.nid, t.tid, GROUP_CONCAT(t.tid) 
FROM node n JOIN term_node t ON t.nid = n.nid 
GROUP BY n.nid 
HAVING t.tid = 31;

In which I want to fetch entries in table node that has tid = 31…but then I also want a list of all the tids corresponding to that row (hence the GROUP_CONCAT) even if they are not 31

Using WHERE t.tid = 31 will leave out the tids that are not 31 from the GROUP concat
and using HAVING t.tid = 31 will leave out rows in which the tid column that appears in the GROUPed row is not 31

Either way has the potential to make the GROUP_CONCAT list incomplete or the rows of nodes with at least one tid = 31 incomplete

Is there a way to resolve this such that I am guaranteed to get ALL the nodes in which the node has at least one tid association equals to 31 AND that GROUP_CONCAT will list ALL The list of tids associated with that node?

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1 Answer

  1. Editorial Team

    This would probably be better as 2 queries. GROUP_CONCAT has a limitation on how long the resulting string can be anyways, so it is not reliable unless you know you will always be under the string length limit.

    I would run the first query ‘WHERE tid = 31’, then run a separate query to get all other ids afterwards and combine in code.

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