Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 3434072
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 18, 20262026-05-18T07:39:13+00:00 2026-05-18T07:39:13+00:00

Suppose I am working on a makefile and I have the following variable declaration

  • 0

Suppose I am working on a makefile and I have the following variable declaration at the top:

FILES = file1.cpp file2.cpp file3.cpp

Now suppose I want to compile each of those with a special command without specifying each target like this:

file1.o : file1.cpp
    custom_command file1.cpp
file2.o : file2.cpp
    custom_command file2.cpp
file3.o : file3.cpp
    custom_command file3.cpp

Is there a better way to do this using the $(FILES) variable I declared above?

Something like:

$(FILES:.cpp=.o) : $(FILES)
    custom_command $(FILES)

…only it needs to do this for each file in the $(FILES) variable.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-18T07:39:13+00:00Added an answer on May 18, 2026 at 7:39 am

    Yes. There are what are known as pattern rules. An example is the easiest to understand:

    %.o: %.cpp
           $(CC) -c $(CFLAGS) $(CPPFLAGS) $< -o $@
    

    (remember that Makefiles require tabs). This rule describes how to make an object file from a cpp file.

    If you do not want such a broad rule, you can use what are called static patterns:

    objects = file1.o file2.o file3.o
    
    all: $(objects)
    
    $(objects): %.o: %.cpp
            $(CC) -c $(CFLAGS) $(CPPFLAGS) $< -o $@
    

    Here’s the section on static pattern rules and pattern rules in the GNU Make manual.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

No related questions found

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.