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Suppose I copy an existing list:
existing_list = [ 1, 2, 3 ];
copied_list = existing_list[:]
...
copied_list[2] = 'a' // COW happens here
[Some edits]
I heard that Python uses copy-on-write when either copied_list or existing_list is mutated. Is this true?
Seems to me like an over-complication that requires locking all over the place (think multi-threading).
For clarity: I am not looking for a COW impl. I’m just trying to understand what’s Python standard behavior.
There is no copy-on-write. When you run
copied_list = existing_list[:], a new list is built and populated immediately. Here is the source: http://hg.python.org/cpython/file/2.7/Objects/listobject.c#l467