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Home/ Questions/Q 8862047
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T15:38:03+00:00 2026-06-14T15:38:03+00:00

Suppose I define this structure: struct Point { double x, y; }; How can

  • 0

Suppose I define this structure:

struct Point {
   double x, y;
};

How can I overload the + operator so that, declared,

Point a, b, c;
double k;

the expression

c = a + b;

yields

c.x = a.x + b.x;
c.y = a.y + b.y;

and the expression

c = a + k;

yields

c.x = a.x + k;
c.y = a.y + k; // ?

Will the commutative property hold for the latter case? That is, do c = a + k; and c = k + a; have to be dealt with separately?

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  1. Editorial Team
    Editorial Team
    2026-06-14T15:38:04+00:00Added an answer on June 14, 2026 at 3:38 pm

    Just do it:

    Point operator+( Point const& lhs, Point const& rhs );
    Point operator+( Point const& lhs, double rhs );
    Point operator+( double lhs, Point const& rhs );
    

    With regards to your last question, the compiler makes no
    assumptions concerning what your operator does. (Remember, the
    + operator on std::string is not commutative.) So you
    have to provide both overloads.

    Alternatively, you can provide an implicit conversion of
    double to Point (by having a converting constructor in
    Point). In that case, the first overload above will handle
    all three cases.

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