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Home/ Questions/Q 8822269
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T06:03:53+00:00 2026-06-14T06:03:53+00:00

Suppose I have 2 JPA entities: @Entity public class OwnerEntity { private List<OwnedEntity> subEntities

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Suppose I have 2 JPA entities:

@Entity
public class OwnerEntity {

    private List<OwnedEntity> subEntities

    // ...
}

@Entity
public class OwnedEntity {

    private String quasiUniqueSid;

    private OwnerEntity ownerEntity

    // ...
}

As you can see they have a many to one relationship: an OwnerEntity can have many OwnedEntitys.

What I want to achieve is to assign each OwnedEntity a unique sid based on its owner. So I can have for example 2 owned entities with the same quasiUniqueSid but they cannot have the same owner. Do Hibernate has some built-in functionality for this kind of problem? I can remember other ORMs (not Java related) which could do this thus my question. I’m using the latest Hibernate version (4.1.8)

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  1. Editorial Team
    Editorial Team
    2026-06-14T06:03:55+00:00Added an answer on June 14, 2026 at 6:03 am

    It seems you need a composite key, like this:

    @Entity
    @Table(uniqueConstraints=@UniqueConstraint(columnNames={"quasiUniqueSid","ownerEntity_id"}), name="myUniqueConstraint")
    public class OwnedEntity {
        ...
        String quasiUniqueSid;
        @ManyToOne
        OwnerEntity ownerEntity;
        ...
    }
    

    A full documentation you can find here.

    If you wanna explicitly define the column name for ownerEntity, you can use:

    @JoinColumn(name="ownerEntity_id")
    
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