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Home/ Questions/Q 6071603
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T10:03:58+00:00 2026-05-23T10:03:58+00:00

Suppose I have a base class Shape, and derived classes Triangle, Square, and Circle.

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Suppose I have a base class “Shape”, and derived classes “Triangle”, “Square”, and “Circle”.
A member of “Shape” is an int “shapeType”.

If shapeType==1, then it’s a triangle.
If shapeType==2, then it’s a square.
If shapeType==3, then it’s a circle.

I’m interested in knowing given I have just a “Shape” object that was once a derived-object, if there is a way to “dynamically” down-cast to the proper derived class by using the shapeType value.

I know I can do a hard-code switch statement, roughly like:

Triangle* t;
Square* s;
Circle* c;

switch (shape->shapeType) {
case 1:
   t = (Triangle*)shape;
case 2: 
   ...
}

However, the above requires me to make a pointer of EVERY derived class possibility. I am wondering if there is a way to do this without hard-coding every class, but instead somehow determine the class type map where the key is the shapeType and the value is the class type.

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  1. Editorial Team
    Editorial Team
    2026-05-23T10:03:59+00:00Added an answer on May 23, 2026 at 10:03 am

    If they’ve virtual functions, then use dynamic_cast:

    t = dynamic_cast<Triangle*>(shape);
    if ( t )
    {
         //use t
    }
    

    But take a note: you should try defining the classes and virtual functions in such a way that you would hardly need to use dynamic_cast. Prefer well-defined interface, and polymorphism, in general.

    Here is one example,

    class Shape
    {
       public:
         virtual ~Shape() {} //destructor must be virtual - important!
         virtual double Area() const = 0;
    };
    
    class Triangle : public Shape
    {
       public:
         Triangle(double a, double b, double c);
         virtual double Area() const 
         {
             //calculate area and return it!
         }
    };
    
    Shape *s = new Triangle(10, 20, 30);
    double aread = s->Area(); //calls Triangle::Area()
    

    No need to use shapeType variable.

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