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Home/ Questions/Q 3663728
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T01:33:48+00:00 2026-05-19T01:33:48+00:00

Suppose I have a Book model containing a foreign key to a Publisher model.

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Suppose I have a Book model containing a foreign key to a Publisher model.

How can I display in the Django admin a column with the number of books published by each publisher, in a way that I can use the built-in sorting?

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  1. Editorial Team
    Editorial Team
    2026-05-19T01:33:49+00:00Added an answer on May 19, 2026 at 1:33 am

    I had the same issue (I cannot change my model’s manager to add slow annotations or joins). A combination of two of the answers here works. @Andre is really close, the Django Admin supports modifying the queryset for just the admin, so apply the same logic here and then user the admin_order_field attribute. You still need to add the new admin field to list_display, of course.

    from django.db.models import Count
    
    class EventAdmin(admin.ModelAdmin)
        list_display = (..., 'show_artist_count')
    
        def queryset(self, request):
        # def get_queryset(self, request):    for Django 1.6+
            qs = super(EventAdmin, self).queryset(request)
            return qs.annotate(artist_count=Count('artists'))
    
        def show_artist_count(self, inst):
            return inst.artist_count
        show_artist_count.admin_order_field = 'artist_count'
    
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