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Home/ Questions/Q 715849
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T05:13:59+00:00 2026-05-14T05:13:59+00:00

Suppose I have a C++ class like so: class A { public: A() {

  • 0

Suppose I have a C++ class like so:

class A
{
    public:
        A()
        {

        }

        void SetNewB( const B& _b ) { m_B = _b; }

    private:
        B m_B;
}

In order to unit test something like this, I would have to break A’s dependency on B. Since class A holds onto an actual object and not a pointer, I would have to refactor this code to take a pointer. Additionally, I would need to create a parent interface class for B so I can pass in my own fake of B when I test SetNewB.

In this case, doesn’t unit testing with dependency injection further complicate the existing code? If I make B a pointer, I’m now introducing heap allocation, and some piece of code is now responsible for cleaning it up (unless I use ref counted pointers). Additionally, if B is a rather trivial class with only a couple of member variables and functions, why introduce a whole new interface for it instead of just testing with an instance of B?

I suppose you could make the argument that it would be easier to refactor A by using an interface. But are there some cases where two classes might need to be tightly coupled?

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  1. Editorial Team
    Editorial Team
    2026-05-14T05:13:59+00:00Added an answer on May 14, 2026 at 5:13 am

    I think you’re taking the idea of Unit Testing too far. In this case, A and B are one unit, i.e., A can’t exist without B. First, test B and make sure it passes all of the B-specific unit tests, then once that passes, test A and make sure it behave how it’s supposed to.

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