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Home/ Questions/Q 8259971
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T02:58:54+00:00 2026-06-08T02:58:54+00:00

Suppose I have a dataset: test = data.frame(x=c(1:11), y=as.character(c(1:11))) where the collumn ‘y’ is

  • 0

Suppose I have a dataset:

test = data.frame(x=c(1:11), y=as.character(c(1:11)))

where the collumn ‘y’ is made up of characters/strings.
Now, I would like to change the strings containing two characters (i.e. test[10,2] & test[11,2]) so that those strings start with a character “0”. The result of this would be “010” & “011”, whereas the other strings (with only one character) remain the same.
To me, the logical solution would be:

test[nchar(test[,2])==2,2] = paste(c("0", test[nchar(test[,2])==2,2]), collapse="")

Indeed, only test[10,2] & test[11,2] are affected. The odd thing is though, that the result is test[10,2] = “01011”, and test[11,2] = “01011”. This means that all strings having two characters are pasted together with a preceding “0”. This definitely is not what I would like to see.

What should I do to add only one character to a string in a dataset when certain conditions (of length) are met?
Your answer would be greatly appreciated.

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  1. Editorial Team
    Editorial Team
    2026-06-08T02:58:55+00:00Added an answer on June 8, 2026 at 2:58 am

    use

    paste("0", test[nchar(test[,2])==2,2], sep="")
    

    so for example

    > test[nchar(test[,2])==2,2] = paste("0", test[nchar(test[,2])==2,2], sep="")
    > test
        x   y
    1   1   1
    2   2   2
    3   3   3
    4   4   4
    5   5   5
    6   6   6
    7   7   7
    8   8   8
    9   9   9
    10 10 010
    11 11 011
    

    collapse and sep have different properties

    > paste(1,c(2:3),collapse=',')
    [1] "1 2,1 3"
    > paste(1,c(2:3),sep=',')
    [1] "1,2" "1,3"
    
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