Question

Suppose I have a dictionary a which is

a = {'a':1,'b':2,'c':3,'d':4,'e':5}

Now If I will give size=2 than the output should be like a list of lists in which each list size should be equal to 2 , last list size doesn’t matter, like in this case it should be like this

[[('a', 1), ('c', 3)], [('b', 2), ('e', 5)], [('d', 4)]]

or if size = 3 than it should be like this [[('a', 1), ('c', 3), ('b', 2)], [('e', 5), ('d', 4)]]

Answer 1

First of all convert your dictionary into a list , which you can do easily like this

In [1]: a = {'a':1,'b':2,'c':3,'d':4,'e':5}

In [2]: b = a.items()

In [3]: b
Out[3]: [('a', 1), ('c', 3), ('b', 2), ('e', 5), ('d', 4)]

than use this method to make the chunks of the list for a given size

In [4]: def chunks(c, n):
   ...:     return [c[i:i+n] for i in range(0, len(c), n)]
   ...: 

In [5]: list(chunks(b,2))
Out[5]: [[('a', 1), ('c', 3)], [('b', 2), ('e', 5)], [('d', 4)]]

In [6]: list(chunks(b,3))
Out[6]: [[('a', 1), ('c', 3), ('b', 2)], [('e', 5), ('d', 4)]]