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Home/ Questions/Q 926719
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T19:43:49+00:00 2026-05-15T19:43:49+00:00

suppose I have a file alpha.h: class Alpha { public: template<typename T> void foo();

  • 0

suppose I have a file alpha.h:

class Alpha {
public:
    template<typename T> void foo();
};

template<> void Alpha::foo<int>() {}
template<> void Alpha::foo<float>() {}

If I include alpha.h in more than one cpp file and compile with GCC 4.4, it complains there are multiple definitions of foo<int> and foo<float> across multiple object files. Makes sense to me, so I change the last two lines to:

template<> extern void Alpha::foo<int>() {}
template<> extern void Alpha::foo<float>() {}

But then GCC says:

explicit template specialization
cannot have a storage class

ok… so how am I supposed to do this correctly? I’m worried that C++ doesn’t allow what I’m trying to do in the first place, in which case is there a good idiom that will accomplish the same thing?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T19:43:50+00:00Added an answer on May 15, 2026 at 7:43 pm

    use inline keyword

    template<> inline void Alpha::foo<int>() {}
    

    alternatively, provide implementation in separate cpp file

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