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Home/ Questions/Q 7542541
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T08:11:40+00:00 2026-05-30T08:11:40+00:00

Suppose I have a function that I do not control that looks something like

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Suppose I have a function that I do not control that looks something like the following:

def some_func(foo, bar, bas, baz):
    do_something()
    return some_val

Now I want to call this function passing elements from a dict that contains keys that are identical to the arguments of this function. I could do something like:

some_func(foo=mydict['foo'],
          bar=mydict['bar'],
          bas=mydict['bas'],
          baz=mydict['baz'])

Is there some elegant way I could take advantage of the fact that the keys match the parms to do this less verbosely? I know I could pass the whole dict, but let’s say I either don’t want to or can’t change the function to accept a single dict rather than the individual arguments.

Thanks,
Jerry

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T08:11:42+00:00Added an answer on May 30, 2026 at 8:11 am

    That’s what ** argument unpacking is for:

    some_func(**mydict)
    

    See also Unpacking argument lists in the Python tutorial.

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