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Home/ Questions/Q 6758071
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T13:43:57+00:00 2026-05-26T13:43:57+00:00

Suppose I have a generator whose __next__() function is somewhat expensive and I want

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Suppose I have a generator whose __next__() function is somewhat expensive and I want to try to parallelize the calls. Where do I throw in the parallization?

To be slightly more concrete, consider this example:

# fast, splitting a file for example
raw_blocks = (b for b in block_generator(fin))
# slow, reading blocks, checking values ...
parsed_blocks = (block_parser(b) for b in raw_blocks)
# get all parsed blocks into a data structure
data = parsedBlocksToOrderedDict(parsed_blocks)

The most basic thing is to change the 2nd line to something that does the parallelization. Is there some generator magic that allows one to unpack the generator (on the 3rd) line in parallel? Calling __next__() in parallel?

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  1. Editorial Team
    Editorial Team
    2026-05-26T13:43:57+00:00Added an answer on May 26, 2026 at 1:43 pm

    No. You must call next() sequentially because any non-trivial generator’s next state is determined by its current state.

    def gen(num):
        j=0
        for i in xrange(num):
            j += i
            yield j
    

    There’s no way to parallelize calls to the above generator without knowing its state at each point it yields a value. But if you knew that, you wouldn’t need to run it.

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