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Home/ Questions/Q 6227863
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T09:17:33+00:00 2026-05-24T09:17:33+00:00

Suppose I have a huge list of elements with a structure like: <div class=item>

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Suppose I have a huge list of elements with a structure like:

<div class="item">
    <div class="header"></div>
    <div class="body"></div>
    <div class="meta"></div>
    <div class="..."></div>
    ...
</div><!-- .item -->

I’ve already found an element and now I have to find, let’s say, a ‘.body’. What code will work faster:

$(el).find('.body')

or

$(el).find('.body').eq(0)

In other words, will jQuery stop on the first found element or will it loop through all the elements first and only then it will return an element with a chosen index?

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  1. Editorial Team
    Editorial Team
    2026-05-24T09:17:34+00:00Added an answer on May 24, 2026 at 9:17 am

    Your second example will always be slower, because it only calls an additional method on a jQuery object that contains all the elements matching .body.

    The fastest way to get the first matching element is probably the :first selector:

    $(el).find(".body:first")
    

    You could also spare one method call by using the context argument to $(), but benchmarks reveal that’s actually slower:

    $(".body:first", el)  // Slower, don't do that.
    
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