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Home/ Questions/Q 6647719
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T00:34:16+00:00 2026-05-26T00:34:16+00:00

Suppose I have a method def f(s:String *) = s.foreach( x => println(x) )

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Suppose I have a method

def f(s:String *) = s.foreach( x => println(x) )

Now I have an array:

val a = Array("1", "2", "3")

How do I invoke f with elements of a as parameters?

EDIT:

So given a, I want to do the following:

f(a(0), a(1), a(2))  // f("1", "2", "3")
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  1. Editorial Team
    Editorial Team
    2026-05-26T00:34:16+00:00Added an answer on May 26, 2026 at 12:34 am

    There is an operator for that:

    f(a: _*)
    

    This operation is defined in chapter 4.6.2 Repeated Parameters of The Scala Language Specification Version 2.9 and further explained in 6.6 Function Applications:

    The last argument in an application may be marked as a sequence argument, e.g.
    e : _*. Such an argument must correspond to a repeated parameter (§4.6.2) of type
    S * […]. Furthermore, the type of e must conform to scala.Seq[T], for some type T which conforms to S. In this
    case, the argument list is transformed by replacing the sequence e with its elements.


    BTW your f function can be simplified:

    def f(s:String *) = s foreach println
    

    Or better (equals sign is discouraged as it suggests that the method actually returns something, however it “only” return Unit):

    def f(s:String *) {s foreach println}
    
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