Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8731627
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 13, 20262026-06-13T09:16:52+00:00 2026-06-13T09:16:52+00:00

Suppose I have a sample array that looks like this: color_values = [{‘score’: 3,

  • 0

Suppose I have a sample array that looks like this:

color_values = [{'score': 3, 'color': u'blue'}, {'score': 1, 'color': u'red'}, {'score': 4, 'color': u'green'}, {'score': 4, 'color': u'red'}, {'score': 2, 'color': u'blue'}]

How do I write a code in python for a new array which averages the score of all the same colors? So the new array would look like:

color_values = [{'score': 2.5, 'color': u'blue'}, {'score': 2.5, 'color': u'red'}, {'score': 4, 'color': u'green'}]
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-13T09:16:54+00:00Added an answer on June 13, 2026 at 9:16 am

    The simplest (if not the shortest) way to solve this kind of problem is to build a dict from the key to a list of values, and then aggregate it:

    by_color = {}
    for obj in color_values:
        by_color.setdefault(obj['color'], []).append(obj['score'])
    color_values = [{'score': float(sum(value)) / len(value), 'color': key}
                    for key, value in by_color.items()]
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Suppose I have a simple multidimensional structure, like this one: somestr<-array(sample.int(2, 120, replace=TRUE), dim=c(4,5,6))
I have a url that looks like this: http://localhost/store/mens/category/t-shirts/item/a-t-shirt I have a class called
I have a array which contains values like this See below for script sample
My question is very simple, suppose that I have an array like array =
Suppose you have a simple class like this: class foo{ private: int* mData; int
I have an array of stdClass objects that are very simple, every object looks
I have one simple app that suppose to get information from user and send
Lets suppose that I have the following simple query var q = from p
I have a small program that's supposed to sample some value from a device
Let us suppose I have to deal with lots of grandmothers that have lots

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.