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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T08:15:39+00:00 2026-05-16T08:15:39+00:00

Suppose I have a std::vector<Obj *> objs (for performance reasons I have pointers not

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Suppose I have a std::vector<Obj *> objs (for performance reasons I have pointers not actual Objs).

I populate it with obj.push_back(new Obj(...)); repeatedly.

After I am done, I have to delete the pushed-back elements. One way is to do this:

for (std::vector<Obj *>::iterator it = objs.begin(); it != objs.end(); ++it) {
    delete *it;
}

However, I am interested if I can use for_each algorithm to do the same:

#include <algorithm>
...
for_each(objs.begin(), objs.end(), delete);

What do you think?

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  1. Editorial Team
    Editorial Team
    2026-05-16T08:15:40+00:00Added an answer on May 16, 2026 at 8:15 am

    Your problem is that delete is not a function, but rather a keyword and as such you can’t take it’s address.

    In C++0x, there will be a std::default_delete class (used by std::unique_ptr), which you could use, or – as everyone’s saying – writing one yourself would be trivial (the standard one also raises a compile error, if you try to delete an incomplete type).

    #include <vector>
    #include <algorithm>
    #include <memory>
    
    int main()
    {
        std::vector<int*> vec;
        std::for_each(vec.begin(), vec.end(), std::default_delete<int>());
    }
    
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