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Home/ Questions/Q 3990860
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T06:32:44+00:00 2026-05-20T06:32:44+00:00

suppose i have a variable in a seperate php file i.e $imgfile = images/img.jpg;

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suppose i have a variable in a seperate php file i.e

$imgfile = "images/img.jpg";

now i have a php file where i am including a html or another php file i.e

<?php 
include("foo.html");
?>

and in foo.html i have the following code..

<html>
<head>
<title>foo site</title>
</head>
<body>
<img src="<?php echo $imgfile; ?>">

and it is works but i am including that $imgfile many times so i want not to type
<?php echo $imgfile; ?> again and again.. i have seen many scripts that include such files by just typing {$imgfile} but i don’t know how to use it please let me know how can i use such a format..??

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  1. Editorial Team
    Editorial Team
    2026-05-20T06:32:44+00:00Added an answer on May 20, 2026 at 6:32 am

    PHP is a template engine already.
    so, it has shorter form for echo statement, especially for this purpose:

    <?=$imgfile?>
    

    considerable shorter and comparable to {$imgfile}

    Note that to make use of brackets, you’ll have to devise alternatives for loops, conditions and other statements, which will complicate your life.
    while using PHP as a template, you’ll be able to use built-in PHP operators, like foreach or if or include.

    So, it would be better to stick to <?=$imgfile?> syntax.

    Just make sure you have short_open_tags setting turned on

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