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Home/ Questions/Q 8843057
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T11:07:17+00:00 2026-06-14T11:07:17+00:00

Suppose I have a vector A = 3 5 3 3 2 2 4

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Suppose I have a vector
A =

 3     5     3     3     2     2     4     2     6

I need to produce a new vector B that will contain all these values from the beggining vector A that will result in a unique number of n elements (suppose n=3, for the purpose of this example). The new vector should be B =

 3     5     3     3     2

since up to the fifth element of vector A we have 3 unique values(3,5,2).
Actual vectors are a lot larger, so I would rather need a general solution and preferably by avoiding a loop. Any ideas? Thanks in advance

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  1. Editorial Team
    Editorial Team
    2026-06-14T11:07:18+00:00Added an answer on June 14, 2026 at 11:07 am

    You can use unique for this problem. However, be sure to use the 'stable' option.

    A = [3     5     3     3     2     2     4     2     6]; 
    n = 3; 
    
    [x, id] = unique(A,'stable'); 
    
    B = A(1:id(3))
    

    This results in

    B =
    
         3     5     3     3     2
    
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