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Home/ Questions/Q 7547587
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T09:29:29+00:00 2026-05-30T09:29:29+00:00

Suppose I have an abstract class FactorizedDialog . It looks like this (please note

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Suppose I have an abstract class FactorizedDialog. It looks like this (please note that this is just some dummy example)

public abstract class FactorizedDialog extends Dialog {

  public abstract void myMethod();
} 

Now I can do something like this:

FactorizedDialog dialog = new FactorizedDialog() {

            @Override
            public void myMethod() {
                // implementation here
            }
}

As you may have guessed I extend Dialog (which is in fact an abstract class) only to add a method to it so I can override it when I create an anonymous class. Is it possible to implement an interface in java while I instantiate Dialog instead of using my derived abstract class?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T09:29:31+00:00Added an answer on May 30, 2026 at 9:29 am

    No, when you specify the superclass of an anonymous inner class you can either specify a normal class to extend or an interface, but not both. The syntax shown in section 15.9 of the JLS simply doesn’t allow for both.

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