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Home/ Questions/Q 6096711
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T12:57:34+00:00 2026-05-23T12:57:34+00:00

Suppose I have an array of three dimensions: set.seed(1) foo <- array(rnorm(250),dim=c(5,10,5)) And I

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Suppose I have an array of three dimensions:

set.seed(1)
foo <- array(rnorm(250),dim=c(5,10,5))

And I want to create a matrix of each row and layer summed over columns 4, 5 and 6. I can write do this like this:

apply(foo[,4:6,],c(1,3),sum)

But this splits the array per row and layer and is pretty slow since it is not vectorized. I could also just add the slices:

foo[,4,]+foo[,5,]+foo[,6,]

Which is faster but gets abit tedious to do manually for multiple slices. Is there a function that does the above expression without manually specifying each slice?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T12:57:35+00:00Added an answer on May 23, 2026 at 12:57 pm

    I think you are looking for rowSums / colSums (fast implementations of apply)

    colSums(aperm(foo[,4:6,], c(2,1,3)))
    
    > all.equal(colSums(aperm(foo[,4:6,], c(2,1,3))), foo[,4,]+foo[,5,]+foo[,6,])
    [1] TRUE
    
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