Question

Suppose I have an Interface with some properties:

public interface IDummy
{
    string First  {get;set;}
    string Second {get;set;}
    string Third  {get;set;}
    string Fourth {get;set;}
}

Now, I have a class which implements that interface:

public class DummyClass: IDummy
{
    // ...
}

Is it possible, not to implement the interface properties explicitly and instead use DynamicObject? For example:

public class DummyClass: DynamicObject, IDummy
{
    public override bool TryGetMember(GetMemberBinder binder, out object result)
    {
        // Get the value from a Config file or SQLite db or something
    }

    public override bool TrySetMember(SetMemberBinder binder, object value)
    {
        // Get the value to a Config file or SQLite db or something
    }
}

I am just curious if this is possible or not?
Thanks.

Answer 1

No, this is not possible.

If you are implementing an interface, you need to implement all of its members. C# is still a statically typed language, after all.

When you say a type implements an interface, you are saying it conforms to its contract. Not implementing all of the members means that you are not complying with the contract.

The compiler would see your code and will not assume that you have implemented the contract correctly (in a dynamic fashion) – it will fail to compile.