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Home/ Questions/Q 8166071
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T19:44:08+00:00 2026-06-06T19:44:08+00:00

Suppose I have the following code to collect all the possible combinations. abArray =

  • 0

Suppose I have the following code to collect all the possible combinations.

abArray = []
for a in range(minA, maxA, aStep):
  for b in range(minB, maxB, bStep):
    if a < b: continue
    abArray.append((a,b))

Is there a more efficient way to store all possible combinations with a condition rather than using nested for loops?

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  1. Editorial Team
    Editorial Team
    2026-06-06T19:44:09+00:00Added an answer on June 6, 2026 at 7:44 pm

    I think you’re looking for itertools.product:

    from itertools import product
    abGenerator = product(range(minA, maxA, stepA), range(minB, maxB, stepB))
    abArray = (i for i in abGenerator if i[0] < i[1])
    
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