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Home/ Questions/Q 5977337
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T21:21:22+00:00 2026-05-22T21:21:22+00:00

Suppose I have the following NumPy array: a = np.array([1,2,3,1,2,1,1,1,3,2,2,1]) How can I find

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Suppose I have the following NumPy array:

a = np.array([1,2,3,1,2,1,1,1,3,2,2,1])

How can I find the most frequent number in this array?

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  1. Editorial Team
    Editorial Team
    2026-05-22T21:21:23+00:00Added an answer on May 22, 2026 at 9:21 pm

    If your list contains all non-negative ints, you should take a look at numpy.bincounts:

    http://docs.scipy.org/doc/numpy/reference/generated/numpy.bincount.html

    and then probably use np.argmax:

    a = np.array([1,2,3,1,2,1,1,1,3,2,2,1])
    counts = np.bincount(a)
    print(np.argmax(counts))
    

    For a more complicated list (that perhaps contains negative numbers or non-integer values), you can use np.histogram in a similar way. Alternatively, if you just want to work in python without using numpy, collections.Counter is a good way of handling this sort of data.

    from collections import Counter
    a = [1,2,3,1,2,1,1,1,3,2,2,1]
    b = Counter(a)
    print(b.most_common(1))
    
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