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Home/ Questions/Q 8602331
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T02:03:37+00:00 2026-06-12T02:03:37+00:00

Suppose I have this: def incrementElements(x): return x+1 but I want to modify it

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Suppose I have this:

def incrementElements(x):
   return x+1

but I want to modify it so that it can take either a numpy array, an iterable, or a scalar, and promote the argument to a numpy array and add 1 to each element.

How could I do that? I suppose I could test argument class but that seems like a bad idea. If I do this:

def incrementElements(x):
   return numpy.array(x)+1

it works properly on arrays or iterables but not scalars. The problem here is that numpy.array(x) for scalar x produces some weird object that is contained by a numpy array but isn’t a “real” array; if I add a scalar to it, the result is demoted to a scalar.

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  1. Editorial Team
    Editorial Team
    2026-06-12T02:03:39+00:00Added an answer on June 12, 2026 at 2:03 am

    You could try

    def incrementElements(x):
        x = np.asarray(x)
        return x+1
    

    np.asarray(x) is the equivalent of np.array(x, copy=False), meaning that a scalar or an iterable will be transformed to a ndarray, but if x is already a ndarray, its data will not be copied.

    If you pass a scalar and want a ndarray as output (not a scalar), you can use:

    def incrementElements(x):
        x = np.array(x, copy=False, ndmin=1)
        return x
    

    The ndmin=1 argument will force the array to have at least one dimension. Use ndmin=2 for at least 2 dimensions, and so forth. You can also use its equivalent np.atleast_1d (or np.atleast_2d for the 2D version…)

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