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Suppose I have two modules:
a.py:
import b print __name__, __file__ b.py:
print __name__, __file__ I run the ‘a.py’ file. This prints:
b C:\path\to\code\b.py __main__ C:\path\to\code\a.py Question: how do I obtain the path to the __main__ module (‘a.py’ in this case) from within the ‘b.py’ library?
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