Question

Suppose I have xml file with contents like this:

<example name={name}/>

Is it possible to load this file from Scala and have {name} replaced with the value of the name in scope?

So something like XML.loadFile, but that does databinding in the same way as Scala’s XML literal.

Note that more complex examples should work as well, e.g.

<example name={name}>
   {for (hobby <- hobbies) yield <hobby>{hobby}</hobby>}
</example>

Answer 1

object XmlBinder {

  // "twitter" at "http://maven.twttr.com"
  // "com.twitter" %% "util-eval" % "3.0.0"
  import com.twitter.util.Eval
  import scala.xml.Elem

  private val template =
    """|<example name={name}>
       |  {for (hobby <- hobbies) yield <hobby>{hobby}</hobby>}
       |</example>""".stripMargin

  val name = "name"
  val hobbies = List("hobby 1", "hobby 2")

  def bind(): Elem = new Eval()("import XmlBinder._\n" + template)
}