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Home/ Questions/Q 7733197
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T06:55:29+00:00 2026-06-01T06:55:29+00:00

Suppose I setup test2.js as follows module.exports.doPrint = doPrint; var dummy = initial; function

  • 0

Suppose I setup test2.js as follows

module.exports.doPrint = doPrint;

var dummy = "initial";

function doPrint(callback) {
    setInterval(function() {
        console.log(dummy);
        callback();
    }, 1000);   
}

I then have test1.js

var test2 = require("./test2");
test2.doPrint(function() {
    console.log("changing");
    test2.dummy = "new value";
});

When I run test1.js I get the following

initial
changing
initial
changing

In other words the value of dummy in test2.js never gets changed to the new value. Can someone explain what is happening here?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T06:55:30+00:00Added an answer on June 1, 2026 at 6:55 am

    It does not change the value because dummy is a local variable (can’t be accessed from outside – variables local to the module will be private). To make it work you can change test2.js to this:

    module.exports.doPrint = doPrint;
    
    function doPrint(callback) {
        var that=this;
        this.dummy = "initial";
        setInterval(function() {
            console.log(that.dummy);
            callback();
        }, 1000);   
    }
    

    or use:

    module.exports.doPrint = doPrint;
    module.exports.get = get;
    module.exports.set = set;
    
    var dummy = "initial";
    
    function get(){
        return dummy
    }
    
    function set(new_value){
        dummy=new_value;
    }
    
    
    function doPrint(callback) {
        setInterval(function() {
            console.log(dummy);
            callback();
        }, 1000);   
    }
    

    and test2.set("new value"); to change the value, if you want it to be a local variable.

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