Question

Suppose I want to render an arrow in CSS, which should have a head, a tail and flexible width so it can contain text. I can of course create multiple divs to get what I want, but how can this be done in CSS3?

I can use multiple background images:

div.arrow{
    background: url('arrowtail.png') left no-repeat, url('arrowhead.png') right no-repeat;
}

The html:

<div class="arrow">This text is on a transparent background</div>

This gives me an div with an arrow-head and tail, and a transparent middle-section.
It does not seem possible specify the color to the middle section.

With only one background-image, you could do this:

div.arrow{ background: red url('some_image.png') no-repeat; }

I know this is doable in lots of ways, but is the background-color property really lost from the shorthand definition?

Answer 1

No, it’s not exactly lost from the shorthand declaration. You can still specify the background color, but only for the last (middle) layer (regardless of whether you put an image there):

div.arrow {
    background: url('arrowtail.png') left no-repeat, 
                url('arrowhead.png') right no-repeat, 
                red;
}

Note that for your scenario, your images may have to have completely opaque backgrounds. The background color will show under any transparent pixels of your images.

jsFiddle demo

---

Declaring background-color separately, however, may be much better for your scenario as it lets you use different colors based on the same background images (if you’re good with transparent pixels on the parts of your images to be filled with the CSS background color):

div.arrow {
    background: url('arrowtail.png') left no-repeat, 
                url('arrowhead.png') right no-repeat;
}

/* Assuming your red arrow has this ID */
#red {
    background-color: red;
}

jsFiddle demo