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Home/ Questions/Q 7092965
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T08:22:48+00:00 2026-05-28T08:22:48+00:00

Suppose I’m creating a session class, with relevant implementation as below: public class Session()

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Suppose I’m creating a session class, with relevant implementation as below:

public class Session()
{
    private $id;
    private $user;
}

The $user field contains an object of type User if the session is logged in, and is null if the session is not logged in to the site. The $id is the session id.

Suppose I now want to find out whether or not the user is logged in. Obviously I could check to see if $user is null, if it is then the user isn’t logged in – something like this:

public class Session()
{
    private $id;
    private $user;

    public function isLoggedIn()
    {
        return !is_null($user);
    }
}

Alternatively, I could store a boolean session variable, $loggedIn or something, set to false on log in and otherwise initialised in the constructor to be false to test against instead:

public class Session()
{
    private $id;
    private $user;
    private $loggedIn;

    public function isLoggedIn()
    {
        return $loggedIn;
    }
}

Would one approach produce better performance than the other here? If so, which, and why? Alternatively, is one approach preferable to the other for any reason unrelated to performance?

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  1. Editorial Team
    Editorial Team
    2026-05-28T08:22:49+00:00Added an answer on May 28, 2026 at 8:22 am

    Simpler is better. If you introduce a new variable to track whether or not $user is null, then you also introduce the possibility that is_null($user) and $loggedIn don’t match. Avoiding the hassle of having to worry about that is worth much more than any possible micro-optimization you may gain in performance.

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