Question

Suppose,

int numbers [20];
int * p;

I think this is statement is valid

p = numbers;

But this is not

numbers = p;

Because numbers is an array, operates as a constant pointer, and we cannot assign values to constants. So if we go by this then we cannot use *numbers while initializing the array?

Answer 1

int numbers [20]; int * p;

I think this is statement is valid

p = numbers;

Yes

But this is not

numbers = p;

Because numbers is an array, operates as a constant pointer, and we cannot assign values to constants.

numbers is not a constant pointer, it is a non modifiable lvalue so you cannot assign to it.

sizeof(int) returns the size of an integer on any particular implementation

sizeof(int*) returns the size of a pointer to an integer.

return type of sizeof() is size_t (unsigned)