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Home/ Questions/Q 6350457
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T21:48:47+00:00 2026-05-24T21:48:47+00:00

Suppose I’ve this nested loop for (int a=1; a<MAX_A; ++a) for (int b=1; b<MAX_B;

  • 0

Suppose I’ve this nested loop

for (int a=1; a<MAX_A; ++a)
  for (int b=1; b<MAX_B; ++b)
    for (int c=1; c<MAX_C; ++c)
    {
       do_something(a, b ,c);
    }

and I reuse this loop in various part of my code, changing the function do_something. It’s quite boring to rewrite every time the first three lines. In python for example I would created a generator to return an iterator (1, 1, 1), (1, 1, 2), ... or something like itertools.product.

In c++ the only solution I’ve in mind is to define a macro. Something better?e

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T21:48:48+00:00Added an answer on May 24, 2026 at 9:48 pm

    Use templates:

    template<typename Func>
    inline void do_something_loop(Func f)
    {
        for (int a=1; a<MAX_A; ++a) 
          for (int b=1; b<MAX_B; ++b) 
            for (int c=1; c<MAX_C; ++c) 
            { 
               f(a, b ,c); 
            } 
    }
    

    This can be called with any function pointer or function object that matches the signature, e.g.:

    void do_something(int a, int b, int c) { /* stuff */ }
    
    do_something_loop(do_something);
    

    Or with a function object:

    struct do_something
    {
        void operator()(int a, int b, int c) { /* stuff */ }
    };
    
    do_something_loop(do_something()); 
    

    Or if your compiler supports C++11, even with a lambda:

    do_something_loop([](int a, int b, int c) { /* stuff */ });
    

    Note that you could also declare the f parameter as a function pointer with the signature void(*f)(int,int,int) instead of using a template, but that’s less flexible (it won’t work on function objects (including the result of std::bind) or lambdas).

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