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Editorial Team
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Asked: 2026-05-17T15:05:48+00:00

suppose the following is the asm code 8048deb: e8 41 05 00 00 call

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suppose the following is the asm code

 8048deb:       e8 41 05 00 00          call   8049331 <explode_bomb>
 8048df0:       03 73 f4                add    -0xc(%ebx),%esi
 8048df3:       83 c3 04                add    $0x4,%ebx
 8048df6:       8d 45 f8                lea    -0x8(%ebp),%eax
 8048df9:       39 c3                   cmp    %eax,%ebx
 8048dfb:       75 e7                   jne    8048de4 <phase_2+0x22>

I set a breakpoint at the last line, by this time, i am expecting both %eax and %ebx to have something stored in them.

In gdb, i do

p/x $ebx

and get:

No registers.

What does this error mean? How can i get the current content stored in a register?

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1 Answer

  1. Editorial Team

    p/x $ebx works just fine for me. (Or rather, p/x $rbx, because i’m testing in a 64-bit OS, but I imagine that p/x $ebx would work in 32-bit.) The application must be running. If I try to do p/x $rbx when the application has not started or has already exited, I do get “no registers”. Are you sure that the breakpoint is hit?

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