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Home/ Questions/Q 9231741
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T06:08:41+00:00 2026-06-18T06:08:41+00:00

Suppose there is a text file containing these in the fallowing style: name: natalie,

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Suppose there is a text file containing these in the fallowing style:

      name: natalie, sarah
      surname: parker
      age: 24
      contry: dubai

I want to get natalie and sarah as the name, parker as the surname and so on. After this, somewhere in my code I need variables name, surname, age (as natalie, sarah, parker, 24 etc..).

I think, first I need to read file and store it in an array and than parse it with using delimiters which are : ” “(space) or “:” in order to parse <surname: parker> this one, and also use “,” comma as a delimiter in order to parse <natalie, sarah>.

I could store the text in an array or use getline(textfile, size) for getting the lines, because I need exactly one line in each time. Which is the most suitable do you think? And how we can do the parsing?

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  1. Editorial Team
    Editorial Team
    2026-06-18T06:08:43+00:00Added an answer on June 18, 2026 at 6:08 am

    I could think of something like this (simplified; no error checking or optimization and such; this is untested, but should work):

    std::ifstream file(myfile);
    std::string line;
    
    std::map<const std::string, std::string> dataset;
    
    while (file >> line) {
        size_t var_start = line.find_first_not_of(" \t"); // get beginning of the variable name
        size_t var_end = line.find_first_of(":"); // get the end of the variable name
        if (var_start == std::string::npos || var_end == std::string::npos) // any not found?
            continue; // skip this line
        std::string var_name = line.substr(var_start, var_end - var_start); // get the variable name
        std::string var_value = line.substr(var_end + 1); // get the variable content
    
        // now do something, e.g. safe it
        dataset[var_name] = var_value;
    }
    
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